1948 U.S. National Championships – Women's Singles

1948 U.S. National Championships – Women's Singles

Women's Singles
1948 U.S. National Championships
Champion Margaret Osborne duPont[1]
Runner-up Louise Brough
Final score 4–6, 6–4, 15–13

Third-seeded Margaret Osborne duPont defeated Louise Brough 4–6, 6–4, 15–13 in the final to win the Women's Singles tennis title at the 1948 U.S. National Championships.[1][2]

Contents

  • Seeds 1
  • Draw 2
    • Key 2.1
    • Final Eight 2.2
  • References 3

Seeds

The seven seeded U.S. players are listed below. Margaret Osborne duPont is the champion; others show in brackets the round in which they were eliminated.[3]


  1. Louise Brough (Finalist)
  2. Doris Hart (Quarterfinalist)
  3. Margaret Osborne duPont (Champion)
  4. Pat Canning Todd (Semifinalist)
  5. Shirley Fry (Third round)
  6. Beverly Baker (Quarterfinalist)
  7. Gussy Moran (Semifinalist)

Draw

Key

  • Q = Qualifier
  • WC = Wild Card
  • LL = Lucky Loser
  • r. = retired

Final Eight

  Quarterfinals Semifinals Finals
                                       
  7   Gussy Moran 6 6  
2   Doris Hart 4 4  
  7   Gussy Moran 8 4  
  3   Margaret Osborne duPont 10 6  
3   Margaret Osborne duPont 1 6 6
    Beverly Baker 6 2 0  
    3   Margaret Osborne duPont 4 6 15
  1   Louise Brough 6 4 13
  1   Louise Brough 6 6  
  Virginia Kovacs 3 2  
  1   Louise Brough 6 6
  4   Pat Canning Todd 3 3  
4   Pat Canning Todd 6 6  
    Madge Vosters 3 1  

References

  1. ^ a b Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York City]: New Chapter Press. p. 471.  
  2. ^ "Exciting Game for Tennis Title.".  
  3. ^